**The Oxygen MPA**

The form of the oxygen MPA is unlike that of any other element. It is ovoid and encloses two
spirally-coiled bodies, one 'positive,' the other 'negative,' revolving rapidly in opposite directions about a
common axis parallel to their length. Each spiral body is a chain of fifty-five much smaller spheres containing two
UPAs (N2), one (+) and the other (−). Each body is shaped like a spring with five coils and has a brilliantly lit
point shining on each coil. This point is actually a globe containing seven UPAs. The major difference between the
two spirals is in their central globes. In the positive spiral, denoted (+), the globes (called 'O_{7}')
contain a central (+) UPA surrounded by a face-centred cubic array of six UPA, three (+) and three (−). In the
negative spiral, denoted (−), the globes (called 'O_{7}′') contain a central (−) UPA, about which are
arranged three (+) UPAs and three (−) UPAs, two being perpendicular to each other and inclined to the third pair,
which lies on a line with the central UPA. The two spirals spin around their shared axis so fast as to present to
micro-psi vision a continuous surface, creating the appearance of a solid cylinder.

**Oxygen MPA = (55N2 + 5O _{7}) + (55N2 +
5O_{7}′)**

The oxygen MPA is formed from two O^{16} nuclei, which contain forty-eight u quarks and
forty-eight d quarks. No reason can yet be given for why micro-psi examination of an oxygen molecule should
disintegrate its two O^{16} nuclei into two chains of particles that are bound states of two subquarks
behaving like dipoles aligned end-to-end and interdispersed by groups of seven subquarks bound together
by strings. The two nuclei provide 288 subquarks, that is, two less than the number of UPAs. Because the MPA
consists of two halves of similar form, this symmetry makes it more plausible that one too many UPAs was
observed in *both* halves than that one half had two fewer UPAs than the other. It also seems more
probable that one too many UPAs was observed in one of the O_{7} and in one of the O_{7}′ than
that one of the N2 in each spiral body was actually a single UPA that went unnoticed. Furthermore, it is
likely that these were a (+) and a (−) UPA because the MPA would then contain 144 (+) UPAs and 144 (−) UPAs,
which would be consistent with it having been formed from two oxygen nuclei with thirty nucleons, a pair of
nucleons having, according to the interpretation of the hydrogen MPA, nine (+) and nine (−) UPAs:

MPA = 144 (+) + 144 (−) = 16[9(+) + 9(−)].

The O_{7} and O_{7}′ groups predicted to have one fewer UPAs will be called,
respectively, 'O_{6}' and 'O_{6}′'.

Each of the fifty-five N2 groups in the (+) spiral is an X-X bound state; each N2 in the (−) spiral is a Y-Y bound state. This is confirmed by the disintegration diagram, which shows that the MPA releases at the E2 stage fifty-five (+) duads (X-X) and fifty-five (−) duads (Y-Y). Thirty-four X subquarks and thirty-four Y subquarks make up the two sets of five globes. The subquark composition of each globe cannot be deduced from the diagram because they were not broken up into their constituents. Two facts, however, allow it to be deduced:

1. The O_{7} was called positive and the O_{7}′ was called negative. In keeping
with the general result that the positivity and negativity of bound states of UPAs refer to the sign of their
electric charge, if a positively charged O_{7} has n X subquarks, each of charge +5/9, and (7−n) Y
subquarks, each of charge −4/9, then its total charge is

(1/9)[5n − 4(7−n)] > 0,

i.e., 9n>28. Therefore, n>4. The facts that the same numbers of X and Y subquarks make up
all the globes and that each spiral contains the same number of globes means that each negatively charged
O_{7}′ is the mirror state of O_{7}, containing n Y subquarks and (7-n) X subquarks. Its total
charge is

(1/9)[5(7−n) −4n] < 0,

i.e., 9n>35. Therefore, n>4. An O_{7} (O_{7}′) with five, six or seven X
(Y) subquarks and, respectively, two, one or no Y (X) subquarks is positively (negatively) charged;

2. The disintegration diagram of the oxygen MPA published in the first edition of *Occult
Chemistry* differs from that above published in the third edition by indicating that the (−) O_{7}′
group released at the E2 stage consists (looking from top to bottom) of a (−) duad (Y-Y), a (−) linear hydrogen
triplet H3′ (d quark = X-2Y) and a second (−) duad (Y-Y), i.e., the O_{7}′ is made up of one X and six Y
subquarks, so that n = 6. This agrees with the second of its three possible configurations deduced above to have a
net negative charge.

In order to be consistent with both the first edition disintegration diagram and their
polarities assigned by Besant & Leadbeater, the O_{7} must be a 6X-Y bound state and its mirror state —
the O_{7}′ — must be an X-6Y bound state. The O_{6} should consist of either six X subquarks or
five X subquarks and one Y subquark, whilst the O_{6}′ must consist, respectively, of either six Y
subquarks or five Y subquarks and one X subquark (either one X is absent from an O_{7} and one X from an
O_{7}′). Remarkably, the total subquark composition of these groups implied by their observed polarities
and by the disintegration diagram of the first edition of *Occult Chemistry* agrees precisely with the
thirty-four X and thirty-four Y subquarks required by theory because:

4O_{7} + 4O_{7}′ + O_{6} + O_{6}’ = 4(6X-Y) + 4(X-6Y) + (6X or
5X-Y) + (6Y or X-5Y) = 34X + 34Y.

This is *convincing* evidence of the correctness of the theory that MPAs are formed from
pairs of atomic nuclei.

The oxygen MPA is an example of small differences to be found occasionally between the
disintegration diagrams of MPAs published in the first and third editions of *Occult Chemistry*. These
"edition variants" are relatively few but highly important as tests of any theory of MPAs because both
compositions of the MPA implied by these diagrams have to be compatible with this theory. In 1895, Besant
published in the Theosophical magazine *Lucifer* descriptions of the MPAs of hydrogen, nitrogen and
oxygen. According to the disintegration diagram she gave there for oxygen, the two spirals broke up at the E2
stage into 110 duads of UPAs pointing in the same direction, that is, (0) duads. Making the plausible
assumption that the O_{7} and O_{7}′ groups have the same compositions in the earlier and
later versions of the oxygen MPA, the subquark composition of the 110 (0) duads must be the same as that of 55
(+) duads and 55 (−) duads. This means that the subquarks in two (0) duads consist of those in one (+) duad
and one (−) duad. A priori, the u and d quarks making up protons and neutrons in atomic nuclei could comprise
up to six differently charged subquark species q_{r} (r = 1-6). Labeling the three recorded types of
duads:

(+) = q_{i} − q_{j}

(−) = q_{k} −
q_{l }
(i, j, k, l, m, n = 1-6)

(0) = q_{m} − q_{n},

then

q_{i} − q_{j} + q_{k} − q_{l} = 2(q_{m} −
q_{n}).

Either:

__Case A__q

and

q_{k} = q_{i} = q_{n} (or q_{m}) ≡ Y,

or:

__Case B__q

and

q_{j} = q_{l} (or q_{k}) = q_{n} (or q_{m}).

But the trivial case B must be wrong because it implies — contrary to observation — that the (+), (−) and (0) duads must have electric charges of the same sign as they consist of the same types of subquarks. Therefore, only case A is permitted and the two edition variants of the oxygen MPA imply that

(+) = X-X,

(−) = Y-Y,

(0) = X-Y.

As the (+) duad is positively charged and the (−) duad is negatively charged, it may be inferred
that X carries a positive charge and that Y carries a negative charge. *The fundamental interpretation of these
types of duads used for the analysis of MPAs — far from being arbitrary — can actually be inferred from the two
edition variants of oxygen and the natural interpretation of Besant's and Leadbeater's terms "positive" and
"negative" as referring to electric polarity.* This refutes the criticism that the interpretation of duads is
model-dependent. Instead, it can be *deduced* from a self-consistent analysis of the observations!